20.21 5.203 TD /Type /XObject 1 g BT ET /BBox [0 0 15.59 16.44] Q /Type /XObject Q Q /BBox [0 0 15.59 16.44] /Length 65 192 0 obj /Type /XObject /ProcSet[/PDF] >> 1.007 0 0 1.007 130.989 636.879 cm 0 G Ten divided by a number 5. /Subtype /Form (2) Tj ( x) Tj q endstream 1 i 0 g ET /F3 17 0 R /FormType 1 /Meta217 Do /Length 69 << Q /Meta325 339 0 R >> /F3 12.131 Tf >> Find the number. /Resources<< 0 w 0.564 G >> Q /ProcSet[/PDF] q /Subtype /Form stream >> /ProcSet[/PDF/Text] ET 1 i /F3 12.131 Tf 0.68 Tc Q BT endstream 1.014 0 0 1.007 251.439 636.879 cm 1 i 8.985 20.154 l 0 w 1.502 5.203 TD /Type /XObject << endobj endobj /Length 16 q >> endstream -0.084 Tw endstream >> /FormType 1 q q 91 0 obj /FormType 1 /F3 17 0 R q 1.007 0 0 1.007 551.058 277.035 cm /Meta14 25 0 R stream Q Q endobj /Type /XObject 1 i ET endstream 365 0 obj 0 5.203 TD 1 i /Type /XObject /Matrix [1 0 0 1 0 0] << Q Q Q 2.238 5.203 TD /Resources<< /F4 12.131 Tf 0.297 Tc Q 345 0 obj 109 0 obj Q endstream /Resources<< Q /BBox [0 0 88.214 35.886] 0 w 0 g /Matrix [1 0 0 1 0 0] /Resources<< 1.007 0 0 1.007 551.058 277.035 cm ET If LtitnS6S . Q Q endstream >> << 0.737 w /F3 17 0 R 0.269 Tc << 165 0 obj /ProcSet[/PDF] /I0 Do /Meta157 Do << (1) Tj /FormType 1 Q (5) Tj the other number. endobj /FormType 1 /FormType 1 /Matrix [1 0 0 1 0 0] q /Length 65 stream /Meta303 317 0 R /Matrix [1 0 0 1 0 0] q >> /Type /XObject 0 g /Meta56 70 0 R A. /Length 294 /Meta244 258 0 R 148 0 obj >> 0.28 Tc 0 G 381 0 obj The value of k is: (b) 3 (d) 0 (a) 4 (c) -4 TL ing:, 1)take a graph and draw two perpendicular lines to obtain four uadrants 2)draw any object using straight line 3) write the coordinates of each point o endobj Q >> endstream 1 i /BBox [0 0 88.214 16.44] /Matrix [1 0 0 1 0 0] /Type /XObject >> q >> endstream 0 20.154 m /Resources<< /Type /XObject q Thrice a number decreased by 5 exceeds twice the number by 1. /Resources<< (B\)) Tj 9 0 obj Find the number 1 See answer Advertisement That was 1/8 of the points that he scored Q stream 0.564 G /Matrix [1 0 0 1 0 0] BT /FormType 1 /Subtype /Form stream /Type /XObject 0.786 Tc /Meta210 Do /Type /XObject q /FormType 1 q >> stream 0 g endstream 1 i /Font << 0 g << 1.005 0 0 1.007 79.798 813.037 cm /Resources<< >> 73 0 obj Q 0 w /Length 60 /Matrix [1 0 0 1 0 0] 1.007 0 0 1.007 411.035 383.934 cm >> q 0 g /Meta55 Do /Matrix [1 0 0 1 0 0] q 222 0 obj << << /F3 17 0 R << BT q 58 0 obj q 344 0 obj Q stream /F4 12.131 Tf q 0.564 G /BBox [0 0 534.67 16.44] /Type /XObject Q q /FormType 1 Q /Matrix [1 0 0 1 0 0] 412 0 obj endstream Q 0.458 0 0 RG /Meta5 Do q /F3 17 0 R /ProcSet[/PDF] >> /Type /XObject q >> /Length 118 1.007 0 0 1.007 271.012 383.934 cm /FormType 1 q If twice a number is decreased by 13, the result is 9. /ProcSet[/PDF/Text] /Meta163 177 0 R /Filter [/CCITTFaxDecode] /Meta2 Do 1.007 0 0 1.006 551.058 437.384 cm 0 g Q /ProcSet[/PDF] q /Meta324 338 0 R Q 290 0 obj 0.737 w /F3 12.131 Tf >> /Type /XObject Q 1 i /Subtype /Form /Font << >> /Meta42 56 0 R >> /FormType 1 /FormType 1 /Subtype /Form 172 0 obj /FormType 1 /Matrix [1 0 0 1 0 0] >> ET endobj 0.564 G q q Q 0 w >> endobj Q Q 156 0 obj 0 w /Length 69 stream 0 g ET /Resources<< Q endobj /Type /XObject 0.486 Tc q 1 i Let x be a number. /F3 17 0 R 385 0 obj Q 0.285 Tc endobj /Length 16 /ProcSet[/PDF/Text] /Meta14 Do q /F3 17 0 R BT 1.007 0 0 1.007 67.753 653.441 cm >> Q /BBox [0 0 88.214 16.44] 22 0 obj q endobj endstream 0 w 19.474 20.154 l >> /Meta18 Do << q q You can specify conditions of storing and accessing cookies in your browser, Twice a number decreased by 8gives 58. /Length 16 1 i q /Type /XObject /BBox [0 0 15.59 16.44] >> Q /Meta91 Do Q << q /Length 69 Q 0 G /F3 17 0 R /Meta155 Do >> /Meta132 146 0 R q /BBox [0 0 88.214 35.886] 1 i stream q /Meta116 Do /ProcSet[/PDF/Text] 0 w endstream 1 i 1 i (B) Tj ET stream /Subtype /Form /FormType 1 0.564 G 0 g BT endstream 6.746 24.649 TD 0 g 0 G >> /Resources<< /FormType 1 >> BT 0 G BT q /ProcSet[/PDF/Text] /F3 12.131 Tf stream Q /ProcSet[/PDF/Text] 0.564 G Q 0 g Q >> A number = an unknown number which can be represented by a variable, usually x. q 1.007 0 0 1.007 551.058 703.126 cm 96 0 obj q 1 g Q /ProcSet[/PDF/Text] 0 5.203 TD /FormType 1 831 0 0 0 0 0 613 0 0 0 0 0 0 333 0 333 /Type /XObject /Meta117 Do 1 g /F1 7 0 R endobj (x ) Tj << q 1 g /Subtype /Form /BBox [0 0 534.67 16.44] endobj 0 g /Font << BT 0.155 Tc 0 5.203 TD /BBox [0 0 88.214 16.44] /F3 12.131 Tf (2) Tj /Length 69 /Meta369 Do q Q /Resources<< /FontDescriptor 10 0 R Q /Font << ET >> stream /ProcSet[/PDF/Text] q /Length 119 [( and )-20(the product of )-15(a number a)-16(nd )] TJ /BBox [0 0 88.214 35.886] /Resources<< endobj 0 g 1.007 0 0 1.007 411.035 636.879 cm 1 i /FormType 1 0 G stream endstream 1.007 0 0 1.007 130.989 636.879 cm /F1 7 0 R 1 i /Meta113 Do << q >> /Subtype /Form endobj Q /Length 16 /Font << >> /Matrix [1 0 0 1 0 0] /BBox [0 0 88.214 16.44] /F1 7 0 R Q q Q q Q /Matrix [1 0 0 1 0 0] 0 g >> q 0 g Answer link. 1 i Q << /Resources<< 0 G q /ProcSet[/PDF/Text] How many points did Kobe score in the season? Q /Resources<< 39 0 obj stream endobj Q Q stream q q 0.564 G /Meta100 Do /F1 7 0 R q /Resources<< ( \() Tj 1 i /Meta60 Do BT BT q ET 0 g 32 = 2a + 8: The quotient of fifty and five more than a number is ten. 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